#include <iostream>
using namespace std;
// stack이필요하다.
// 1. type을만들지않은경우
// 단점: Stack 2개이상필요한경우복잡해진다.
int buf[10];
int top = 0;
void push( int a )
{
buf[top++] = a;
}
int pop()
{
return buf[--top];
}
void main()
{
push( 10 );
push( 20 );
cout << pop() << endl;
cout << pop() << endl;
}
// 2. Stack이라는Type을먼저만들자- 구조체사용
struct Stack
{
int buf[10];
int top;
};
void init( Stack* s ) { s->top = 0; }
void push( Stack* s, int n) { s->buf[s->top++] = n; }
int pop( Stack* s ) { return s->buf[--s->top]; }
int main()
{
Stack s1;
Stack s2;
init( &s1 );
push( &s1, 10 );
cout << pop( &s1 ) << endl;
return 0;
}
// 3. 함수와Data를묶어서표현하자.
// Type 설계의원칙: 잘못사용하기어렵게만들어라.
struct Stack
{
private: // 멤버함수만접근할수있다.
int buf[10];
int top;
public: // 모든곳에서접근할수있다.
// 멤버함수: 멤버Data에바로접근할수있다.
//void init() { top = 0; } //생성자역할.
Stack() { top = 0; }
void push( int n ) { buf[top++] = n; }
int pop() { return buf[--top]; }
};
void main()
{
Stack s1;
Stack s2;
//s1.init();
s1.push(10);
//s1.top = 100; // private: 영역!!
cout << s1.pop() << endl;
}
// 4. 동적메모리할당사용
struct Stack
{
private:
int* buf;
int top;
public:
// 생성자: 객체를생성하면자동으로호출되는함수
Stack( int sz = 10 )
{
top = 0;
buf = new int[sz];
}
// 객체가파괴될때자동으로호출된다.
~Stack() { delete[] buf; }
void push( int n ) { buf[top++] = n; }
int pop() { return buf[--top]; }
};
void main()
{
Stack s1;
Stack s2(30);
s1.push(10);
cout << s1.pop() << endl;
}
// 5. Template 기반의Stack
template <typename T>
struct Stack
{
private:
T* buf;
int top;
public:
// 생성자: 객체를생성하면자동으로호출되는함수
Stack( int sz = 10 )
{
top = 0;
buf = new T[sz];
}
// 객체가파괴될때자동으로호출된다.
~Stack() { delete[] buf; }
void push( T n ) { buf[top++] = n; }
T pop() { return buf[--top]; }
};
void main()
{
Stack<int> s1; // template class( struct )의객체를생성하는방법
Stack<double> s2(30);
s1.push(10);
cout << s1.pop() << endl;
}
template <typename T>
struct List
{
T buf;
List* link;
List()
{
link = NULL;
}
};
template <typename T>
struct Stack
{
private:
List<T>* pList;
int tail;
public:
// 생성자: 객체를생성하면자동으로호출되는함수
Stack()
{
tail = 0;
}
// 객체가파괴될때자동으로호출된다.
~Stack()
{
}
void push( T n )
{
pList = new pList;
pList->buf = n;
}
T pop()
{
return buf[--top];
}
};
void main()
{
Stack<int> s1; // template class( struct )의객체를생성하는방법
s1.push(10);
cout << s1.pop() << endl;
}
#include <iostream> using namespace std; template <typename T> class List { public: T m_Data; List* m_pNext; List(T n, List* next) : m_Data(n), m_pNext(next) {} ~List() { if( m_pNext != NULL ) delete m_pNext; } }; template <typename T> class Stack { List<T>* m_pList; public: Stack(); ~Stack(); bool IsEnd(); void push( T n ); T pop(); }; template<typename T> Stack<T>::Stack() : m_pList(NULL) {} template<typename T> Stack<T>::~Stack() {} template<typename T> bool Stack<T>::IsEnd() { return (m_pList == NULL); } template<typename T> void Stack<T>::push( T n ) { m_pList = new List<T>( n , m_pList ); } template<typename T> T Stack<T>::pop() { if( IsEnd() ) { cout << "Stack is End" << endl; return -1; } List<T>* temp = m_pList; T data = m_pList->m_Data; m_pList = m_pList->m_pNext; temp->m_pNext = NULL; delete temp; return data; } void main() { Stack<int> s1; s1.push( 10 ); s1.push( 20 ); s1.push( 30 ); cout << s1.pop() << endl; cout << s1.pop() << endl; cout << s1.pop() << endl; Stack<double> s2; s2.push( 4.20 ); s2.push( 5.560 ); cout << s2.pop() << endl; cout << s2.pop() << endl; // Stack<char*> s3; // s3.push("문자열??"); // s3.push("출력가능??"); // cout << s3.pop() << endl; // cout << s3.pop() << endl; // cout << s3.pop() << endl; }
6. Single linked list 기반의 template Stack
